25b^2-115b+60=0

Solution for 25b^2-115b+60=0 equation:

25b^2-115b+60=0

a = 25; b = -115; c = +60;
Δ = b2-4ac
Δ = -1152-4·25·60
Δ = 7225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7225}=85$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-115)-85}{2*25}=\frac{30}{50}
=3/5
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-115)+85}{2*25}=\frac{200}{50}
=4
$